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Wondershare Dr Fone 10.3.2 Full Crack With License Key. dr.. Wondershare Dr Fone 10 Crack [Torrent + Serial Key] Free Download. Wondershare Dr.Fone Crack + Keygen: New Pc Toolkit [Latest. Wondershare Dr Fone 4.9.1.0 Crack With Serial Key Latest Full Download Wondershare Dr Fone Keygen Latest Free Download drfonetools.com .Q: Equation of motion with 3 variables using method of undetermined coefficients Consider the equation of motion: $$ma^2\frac{d^2x}{dt^2} = k(x-g)$$ I’ve tried to solve this using the method of undetermined coefficients and found this solution: $$x(t) = \frac{1}{12}g(t)^3 – \frac{1}{24}g(t)^4 + c_1\int g(t)dt + c_2\int g(t)dt$$ Where: $m = g(0) = 0$, $k = -2.5$, $a = 2$ and $g(t) = 4t$. I think I messed up somewhere in the calculations. Any ideas what went wrong? EDIT: Did some calculations by hand and verified that this solution is correct. A: Equation $ma^2\frac{d^2x}{dt^2} = k(x-g)$ is an application of Lagrange inversion formula. We have $$L = \frac {1}{2} m a^2 \dot x^2 – k(x-g) \implies \ddot x = -\frac{k}{a^2 m} (x-g) + \frac{g’}{a^2 m}$$ or rearranged $$ m a^2 \dot x^2 + 2k\dot x – g’ = 0$$ Integrating, we get $$x = \frac{1}{a^2 m} g(t) + \frac{1}{a^2 m} \int_0^t ds\, g'(s)$$ $$\implies x(t) = \frac{1}{12}g(t)^3 – \frac{1}{24}g(t)

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